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#479 bbaabbabba=a

Original presentation

\( \left\langle a, b \;\middle|\; b^{2} a^{2} b^{2} a b^{2} a = a \right\rangle \)

Modified presentation

\( \left\langle a, b, c, d \;\middle|\; c a^{2} c a c a = a,\; c = b^{2},\; d = b^{2} a \right\rangle \)

Complete rewriting system

Using reversed recursive path order (RevRPOCmp) with \(d < a < b < c\):

\( \begin{aligned} c &\rightarrow b^{2} \\ b^{2} a &\rightarrow d \\ d a d^{2} &\rightarrow a \\ d a d a &\rightarrow a^{2} d^{2} \\ d a^{2} &\rightarrow a^{2} d^{4} \end{aligned} \)