#419 aababababa=babaaa

Original presentation

\( \left\langle a, b \;\middle|\; a^{2} b a b a b a b a = b a b a^{3} \right\rangle \)

\( \left\langle a, b, c, d \;\middle|\; a^{2} c^{4} = c^{2} a^{2},\; c = d,\; d = b a \right\rangle \)

Using reversed recursive path order (RevRPOCmp) with \(d < a < b < c\):

\( \begin{aligned} c &\rightarrow d \\ b a &\rightarrow d \\ d^{2} a^{2} &\rightarrow a^{2} d^{4} \end{aligned} \)