Skip to content

#185 baaabbba=aaa

Original presentation

\( \left\langle a, b \;\middle|\; b a^{3} b^{3} a = a^{3} \right\rangle \)

Modified presentation

\( \left\langle a, b, c, d \;\middle|\; b c a d a = c a,\; c = a^{2},\; d = b^{3} \right\rangle \)

Complete rewriting system

Using recursive path order (RPOCmp) with \(a < d < b < c\):

\( \begin{aligned} c &\rightarrow a^{2} \\ b^{3} &\rightarrow d \\ b d &\rightarrow d b \\ b a^{3} &\rightarrow d a^{3} d a d a \\ d a^{3} d a d a d a &\rightarrow a^{3} \\ d a^{3} d a d a^{4} &\rightarrow a^{5} d a d a d a \end{aligned} \)