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#452 baabaabbaa=aaaba

Original presentation

\( \left\langle a, b \;\middle|\; b a^{2} b a^{2} b^{2} a^{2} = a^{3} b a \right\rangle \)

Modified presentation

\( \left\langle a, b, c, d \;\middle|\; c a c a d = a^{3} c,\; c = b a,\; d = b c a \right\rangle \)

Complete rewriting system

Using recursive path order (RPOCmp) with \(c < d < a < b\):

\( \begin{aligned} b a &\rightarrow c \\ b c a &\rightarrow d \\ a^{3} c &\rightarrow c a c a d \\ c a^{2} c &\rightarrow d c a d \\ b c^{2} a c a d &\rightarrow d a^{2} c \\ b d c a d &\rightarrow d a c \\ a^{3} d c a d &\rightarrow c a c a d a^{2} c \\ c a^{2} d c a d &\rightarrow d c a d a^{2} c \end{aligned} \)