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#271 baaaaabbba=abbaa

Original presentation

\( \left\langle a, b \;\middle|\; b a^{5} b^{3} a = a b^{2} a^{2} \right\rangle \)

Modified presentation

\( \left\langle a, b, c, d \;\middle|\; b c^{2} d b a = d c,\; c = a^{2},\; d = a b^{2} \right\rangle \)

Complete rewriting system

Using recursive path order (RPOCmp) with \(a < d < b < c\):

\( \begin{aligned} c &\rightarrow a^{2} \\ b a^{4} d b a &\rightarrow d a^{2} \\ a b^{2} &\rightarrow d \\ b a^{4} d b d &\rightarrow d a d \\ b a^{4} d^{2} a^{2} &\rightarrow d a^{5} d b a \\ a b d a^{2} &\rightarrow d a^{4} d b a \\ b a^{4} d^{2} a d &\rightarrow d a^{5} d b d \\ a b d a d &\rightarrow d a^{4} d b d \end{aligned} \)