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#327 abaabbaba=babaa

Original presentation

\( \left\langle a, b \;\middle|\; a b a^{2} b^{2} a b a = b a b a^{2} \right\rangle \)

Modified presentation

\( \left\langle a, b, c, d \;\middle|\; c a b^{2} c = b c a,\; c = a b a,\; d = a b^{2} a \right\rangle \)

Complete rewriting system

Using reversed recursive path order (RevRPOCmp) with \(b < d < c < a\):

\( \begin{aligned} a b a &\rightarrow c \\ a b^{2} a &\rightarrow d \\ b c a &\rightarrow c a b^{2} c \\ c b a &\rightarrow a b c \\ c b^{2} a &\rightarrow a b d \\ d b a &\rightarrow a b^{2} c \\ d b^{2} a &\rightarrow a b^{2} d \\ b c d &\rightarrow c d b d \\ b c^{2} &\rightarrow c d b c \end{aligned} \)