#215 bababababa=ababbaba
Original presentation
\( \left\langle a, b \;\middle|\; b a b a b a b a b a = a b a b^{2} a b a \right\rangle \)
Modified presentation
\( \left\langle a, b, c, d \;\middle|\; c^{5} = d c^{2},\; c = b a,\; d = a c b \right\rangle \)
Complete rewriting system
Using recursive path order (RPOCmp) with \(c < d < a < b\):
\( \begin{aligned} b a &\rightarrow c \\ a c b &\rightarrow d \\ d c^{2} &\rightarrow c^{5} \\ b d &\rightarrow c^{2} b \\ a c^{2} &\rightarrow d a \\ b c^{5} &\rightarrow c^{2} b c^{2} \end{aligned} \)